JEE Main & Advanced Mathematics Sequence & Series Question Bank Mock Test - Sequences and Series

  • question_answer
    Sum of the series \[\frac{2}{3}+\frac{8}{9}+\frac{26}{27}+\frac{80}{81}+...\]to n terms is

    A) \[n-\frac{1}{2}({{3}^{n}}-1)\]

    B) \[n+\frac{1}{2}({{3}^{n}}-1)\]

    C) \[n+\frac{1}{2}(1-{{3}^{-n}})\]

    D) \[n+\frac{1}{2}({{3}^{-n}}-1)\]

    Correct Answer: D

    Solution :

    [d] \[{{T}_{n}}=\frac{{{3}^{n}}-1}{{{3}^{n}}}=1-{{\left( \frac{1}{3} \right)}^{n}}\] \[{{S}_{n}}=n-\sum\limits_{n=1}^{n}{{{\left( \frac{1}{3} \right)}^{n}}}\] \[=n-\frac{\frac{1}{3}\left[ 1-{{\left( \frac{1}{3} \right)}^{n}} \right]}{\left( 1-\frac{1}{3} \right)}\] \[=n-\frac{1}{2}(1-{{3}^{-n}})=n+\frac{1}{2}({{3}^{-n}}-1)\]


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