A) 381
B) 471
C) 281
D) none of these
Correct Answer: D
Solution :
[d] \[{{100}^{th}}\]term of 1, 11, 21, 31, ?is 1+ (100-1) 10=991.\[{{100}^{th}}\]term of 31, 36, 41, 46, ?is 31 +(100-1) 5=526. let the largest common term be 526. Then. 526=31+(n-1)10 Or n=50.5 But n is an integer; hence n=50. Hence, the larg3est common terms is 31+(50-1)10=521.You need to login to perform this action.
You will be redirected in
3 sec