A) \[n\]
B) \[2n\]
C) \[{{n}^{2}}\]
D) 0
Correct Answer: C
Solution :
[c] if both A and B have n elements in common, then a common ordered pair in A\[\times \]B and B\[\times \]A can have the first element common in n ways and similarly the second element also in n ways. Thus, \[n.n={{n}^{2}}\]elements will be in common.
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