A) {2}
B) {0}
C) \[\phi \]
D) {1}
Correct Answer: C
Solution :
[c] \[A=\{x|{{x}^{3}}-3{{x}^{2}}+2x=0\}\] Consider \[{{x}^{3}}-3{{x}^{2}}+2x=0\] \[\Rightarrow \] \[x({{x}^{2}}-3x+2)=0\] \[\Rightarrow \] \[x(x-2)(x-1)=0\] \[\therefore \] \[A=\{0,1,2\}\] \[B=\{x|{{x}^{2}}-2x=0\}\] Consider \[{{x}^{2}}-2x=0\]\[\Rightarrow \]\[x(x-2)=0\] \[\therefore \] \[B=\{0,2\}\] \[\therefore \] \[B-A=\{\}=\varphi \]You need to login to perform this action.
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