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JEE Main & Advanced Mathematics Sets Question Bank Mock Test - Sets

  • question_answer
    If A=\[\{x|{{x}^{3}}-3{{x}^{2}}+2x=0\}\],B=\[\{x|{{x}^{2}}-2x=0\}\], then B-A is

    A) {2}                  

    B) {0}

    C) \[\phi \] 

    D) {1}

    Correct Answer: C

    Solution :

    [c] \[A=\{x|{{x}^{3}}-3{{x}^{2}}+2x=0\}\] Consider \[{{x}^{3}}-3{{x}^{2}}+2x=0\] \[\Rightarrow \]   \[x({{x}^{2}}-3x+2)=0\] \[\Rightarrow \]   \[x(x-2)(x-1)=0\] \[\therefore \]       \[A=\{0,1,2\}\]             \[B=\{x|{{x}^{2}}-2x=0\}\] Consider \[{{x}^{2}}-2x=0\]\[\Rightarrow \]\[x(x-2)=0\] \[\therefore \]       \[B=\{0,2\}\] \[\therefore \]       \[B-A=\{\}=\varphi \]    


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