A) 40
B) 41
C) 42
D) 43
Correct Answer: B
Solution :
[41] Let R be the set of families having a radio and T be the set of families having a TV. Then \[n(R\cup T)\]=Number of families having at least one of the radio and TV =1003-63=940 n (R)=794 and n(T)=187 Let x be the number of families having both a radio and a TV. Then number of families who have only radio=794-x Number of families who have only TV=187-x From venn diagram, 794-x+x+187-x=940 \[\Rightarrow \]981-x=940 \[\therefore \]x=981-940=41 Hence, the required number of families having both a radio and a TV is 41.You need to login to perform this action.
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