A) \[\pm \frac{A}{2}\]
B) \[\pm \frac{A}{\sqrt{2}}\]
C) \[\pm \frac{A}{3}\]
D) \[\pm \frac{A}{\sqrt{3}}\]
Correct Answer: B
Solution :
[b] \[U=\beta {{x}^{4}}\](Given) \[\therefore {{U}_{\max }}=\beta {{A}^{4}}\] \[K(x)={{U}_{\max }}-U(x)=\beta {{A}^{4}}-\beta {{x}^{4}}=\beta ({{A}^{4}}-{{x}^{4}})\]\[U(x)=\frac{1}{23}K(x)\](Given) \[\therefore \beta {{x}^{4}}=\frac{1}{3}\beta ({{A}^{4}}-{{x}^{4}})\] \[\Rightarrow x=\pm \frac{A}{\sqrt{2}}\]
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