JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Mock Test - Simple Harmonic Motion

  • question_answer
    A particle of mass \[m\] is attached to a spring (of spring constant\[k\]) and has a natural angular frequency\[{{\omega }_{0}}\]. An external force \[F(t)\] proportional to \[\cos \,\omega t\,(\omega \ne {{\omega }_{0}})\] is applied to the oscillator. The time displacement of the oscillator will be proportional to

    A) \[\frac{m}{{{\omega }^{2}}_{0}-{{\omega }^{2}}}\] 

    B) \[\frac{1}{m({{\omega }^{2}}_{0}-{{\omega }^{2}})}\]

    C) \[\frac{1}{m({{\omega }^{2}}_{0}+{{\omega }^{2}})}\]       

    D) \[\frac{m}{{{\omega }^{2}}_{0}+{{\omega }^{2}}}\]

    Correct Answer: B

    Solution :

    [b] for forced oscillations, the displacement is given by  \[x=A\sin (\omega t+\phi )\]With \[A=\frac{{{F}_{0}}/m}{{{\omega }_{0}}^{2}-{{\omega }^{2}}}\]


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