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JEE Main & Advanced Chemistry The Solid State / ठोस प्रावस्था Question Bank Mock Test - Solid State

  • question_answer
    The number of unit cells in 58.5 g of NaCl is nearly

    A) \[6\times {{10}^{20}}\]           

    B) \[1.5\times {{10}^{23}}\]

    C) \[3\times {{10}^{22}}\]

    D) \[0.5\times {{10}^{24}}\]

    Correct Answer: B

    Solution :

    [b] 58.5 g \[NaCl=1mol=6.02\times {{10}^{23}}N{{a}^{+}}C{{l}^{-}}\]units One unit cell contains \[4N{{a}^{+}}C{{l}^{-}}\]units. Hence number of unit cell present \[=\frac{6.02\times {{10}^{23}}}{4}=1.5\times {{10}^{23}}\]


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