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JEE Main & Advanced Chemistry The Solid State / ठोस प्रावस्था Question Bank Mock Test - Solid State

  • question_answer
      The spinel structure (\[A{{B}_{2}}{{O}_{4}}\]) consists of an fee array of \[{{O}^{2-}}\] ions in which the:

    A) A cation occupies one-eighth of the tetrahedral holes and B cation occupies half of octahedral holes

    B) A cation occupies one-fourth of the tetrahedral holes and the B cations the octahedral holes

    C) A cation occupies one-eighth of the octahedral hole and the B cation the tetrahedral holes

    D) A cation occupies one-fourth of the octahedral holes and the B cations the tetrahedral holes

    Correct Answer: A

    Solution :

    [a] fcc array\[\Rightarrow \]no. of \[{{O}^{2-}}\]ions=4 no. of TVs=8 and OVs=4 \[A\to \frac{1}{8}\times 8=1,B\to 4\times \frac{1}{2}=2\] and \[{{O}^{2-}}=4\]so formula of spinel \[=A{{B}_{2}}{{O}_{4}}\]


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