A) \[\frac{{{a}^{3}}}{27}\]
B) \[\frac{{{a}^{3}}}{64}\]
C) \[\frac{{{a}^{3}}}{2\sqrt{2}}\]
D) \[\frac{{{a}^{3}}}{8}\]
Correct Answer: D
Solution :
[d] The centre atom of I will be at corner of 2. Hence cube 2 divide volume by 8. \[\therefore \frac{{{a}^{3}}}{8}=\]Common volume?You need to login to perform this action.
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