A) AgCl has anion Frenkel defect and \[Ca{{F}_{2}}\] has Schottky defects
B) AgCl has cation Frenkel defects and \[Ca{{F}_{2}}\] has anion Frenkel defects
C) AgCl and \[Ca{{F}_{2}}\] have anion Frenkel defects
D) AgCl and \[Ca{{F}_{2}}\] have Schottky defects
Correct Answer: B
Solution :
[b] Since \[A{{g}^{+}}\](cation) is smaller than \[C{{l}^{-}}\](anion) and hence cation is present in voids. In \[Ca{{F}_{2}},C{{a}^{2+}}\]is smaller.
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