question_answer

Consider a cube 1 of body centered cubic unit cell of edge length a. Now atom at the body centre can be viewed to be lying on the comer of another cube 2. Find the volume common to cube 1 and cube 2.

A) \[\frac{{{a}^{3}}}{27}\]                     

B) \[\frac{{{a}^{3}}}{64}\]

C) \[\frac{{{a}^{3}}}{2\sqrt{2}}\]

D) \[\frac{{{a}^{3}}}{8}\]

Correct Answer: D

Solution :

[d] The centre atom of I will be at corner of 2. Hence cube 2 divide volume by 8. \[\therefore \frac{{{a}^{3}}}{8}=\]Common volume?