A) \[\frac{1}{6}\]
B) \[\frac{1}{8}\]
C) \[\frac{1}{4}\]
D) \[\frac{1}{2}\]
Correct Answer: D
Solution :
| [d] Number of \[{{O}^{2-}}\]ions=n |
| Number of tetrahedral voids=2n |
| Number of octahedral voids=n |
| Number of Y ions\[=\frac{n}{2}\], Number of X ions\[=\frac{n}{4}\] |
| Since Y ions are equally distributed among distributed among OVs and TVs. |
| Occupied of octahedral voids \[=\frac{n}{4}+\frac{n}{4}=\frac{n}{2}\] |
| \[\therefore \] Fraction of occupied octahedral void\[=\frac{n/2}{n}=\frac{1}{2}\] |
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