A) 49 g
B) 98 g
C) 70 g
D) 34.3 g
Correct Answer: C
Solution :
\[{{H}_{2}}S{{O}_{4}}+2NaOH\to N{{a}_{2}}S{{O}_{4}}+2{{H}_{2}}O\] For 1 mole \[NaOH\frac{1}{2}\]mole \[{{H}_{2}}S{{O}_{4}}\]required Molar mass of \[{{H}_{2}}S{{O}_{4}}\]=98 g 70 g \[{{H}_{2}}S{{O}_{4}}\]in 100 g solution \[\frac{98}{2}\]g \[{{H}_{2}}S{{O}_{4}}\]in =\[\frac{100}{70}\times 49=70\]g solution.
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