question_answer

A compound of boron X reacts at \[200{}^\circ C\]temperature with \[N{{H}_{3}}\]to give another compound Y which is called as inorganic benzene. The compound Y is a colourless liquid and is highly light sensitive. Its melting point is \[-57{}^\circ C\]. The compound X with excess of \[N{{H}_{3}}\] and at a still higher temperature gives boron nitride (\[{{(BN)}_{n}}\]). The compounds X and Y are respectively:

A) \[B{{H}_{3}}\] and \[{{B}_{2}}{{H}_{6}}\]

B) \[NaB{{H}_{4}}\]and\[{{C}_{6}}{{H}_{6}}\]

C) \[{{B}_{2}}{{H}_{6}}\]and \[{{B}_{3}}{{N}_{3}}{{H}_{6}}\]          

D)  \[{{B}_{4}}{{C}_{3}}\]and \[{{C}_{6}}{{H}_{6}}\]