A) Z is hydrogen
B) Y is \[LiB{{F}_{4}}\]
C) Z and Y are \[{{F}_{2}}\]and \[{{B}_{2}}{{H}_{6}}\] respectively
D) Z is potassium hydroxide
Correct Answer: C
Solution :
[c]\[B(s)\xrightarrow{{{F}_{2}}(Z)}\underset{(X)}{\mathop{B{{F}_{3}}}}\,\xrightarrow{LiH}\underset{(Y)}{\mathop{{{B}_{2}}{{H}_{6}}}}\,+LiB{{F}_{4}}\]You need to login to perform this action.
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