A) \[C{{H}_{4}}>Si{{H}_{4}}>Ge{{H}_{4}}>Sn{{H}_{4}}>Pb{{H}_{4}}\]
B) \[C{{H}_{4}}<Si{{H}_{4}},<Ge{{H}_{4}}<Sn{{H}_{4}}<Pb{{H}_{4}}\]
C) \[C{{H}_{4}}.>Sn{{H}_{4}},>Ge{{H}_{4}}>Sn{{H}_{4}}>Pb{{H}_{4}}\]
D) None of the above
Correct Answer: A
Solution :
[a] Hydride of carbon family is stable when carbon is near to nucleus, thus its attraction is more toward valence shell electron so, it is more stable \[C{{H}_{4}}>Si{{H}_{4}}>Ge{{H}_{4}}>Sn{{H}_{4}}>Pb{{H}_{4}}\]
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