question_answer

In \[S{{O}_{3}}\] molecule, 3 oxygen atoms are attached to sulphur atom through double bonds. Hence, the molecules consist \[3\pi \]-bonds. The types of pi-bonds present in \[S{{O}_{3}}\] molecule are

A) All \[p\pi \]-\[p\pi \] bonds

B) one \[p\pi \]-\[p\pi \] and two \[p\pi \]-\[p\pi \] bonds.

C) one \[p\pi \]-\[p\pi \] and one \[p\pi \]-\[p\pi \] bonds

D) two \[p\pi \]-\[p\pi \] and one \[p\pi \]-\[p\pi \] bonds

Correct Answer: D

Solution :

[d] In gas phase, \[S{{O}_{3}}\] molecule is triangular planar having \[s{{p}^{2}}\]-hybridisation of the S-atom. There are three sigma bonds formed by \[s{{p}^{2}}\]-P overlap and three pi-bonds are by one \[p\pi -p\pi \]overlap and two \[p\pi -d\pi \]overlap.