A) \[CaOC{{l}_{2}}\], \[N{{a}_{2}}S{{O}_{3}}\]
B) \[N{{a}_{2}}S{{O}_{3}}\],\[CaOC{{l}_{2}}\]
C) \[CaC{{l}_{2}}\], \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]
D) \[CaOC{{l}_{2}}\], \[N{{a}_{2}}{{S}_{2}}{{O}_{2}}\]
Correct Answer: D
Solution :
[d] \[CaOC{{l}_{2}}\] acts as bleaching agent while \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\] acts as antichlor according to the following reaction: \[CaOC{{l}_{2}}+{{H}_{2}}O\to Ca{{(OH)}_{2}}+C{{l}_{2}}\] \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}+4C{{l}_{2}}+5{{H}_{2}}O\to 2NaHS{{O}_{4}}+8HCl\]
You need to login to perform this action.
You will be redirected in
3 sec
