A) \[{{\left[ Xe{{O}_{6}} \right]}^{4-}}\]and Xe
B) \[{{\left[ Xe{{O}_{6}} \right]}^{4-}}\]and \[Xe{{O}_{3}}\]
C) \[Xe{{O}_{3}}\] and Xe
D) \[{{H}_{2}}Xe{{O}_{4}}\]and Xe
Correct Answer: A
Solution :
[a] Hydrogen xenate ion, \[{{[HXe{{O}_{4}}]}^{-}}\](oxidation state of Xe=+6) disproportionates slowly in solution to give perxenates, \[{{[Xe{{O}_{6}}]}^{4-}}(O.S.\,of\,Xe=+8)\]and xenon.You need to login to perform this action.
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