question_answer

Ammonia and chlorine are made to react. If ammonia is in excess, products formed are A and B. and when chlorine is in excess the products are C and D, A, B, C and D respectively are

A) \[NC{{l}_{3}}\], HCl  and \[{{N}_{2}}\], \[N{{H}_{4}}Cl\]

B) \[{{N}_{2}}\], \[N{{H}_{4}}Cl\] and  \[NC{{l}_{3}}\], HCl

C) \[{{N}_{2}}\], HCl  and \[{{N}_{2}}\], \[N{{H}_{4}}Cl\]

D) \[{{N}_{2}}\], \[N{{H}_{4}}Cl\] and  \[NC{{l}_{3}}\], HCl

Correct Answer: B

Solution :

[b] When ammonia is in excess: When chlorine is in excess: \[N{{H}_{3}}+HCl\to NC{{l}_{3}}+3HCl\]