A) \[Xe{{O}_{3}}+6HF\to Xe{{F}_{6}}+{{H}_{2}}O\]
B) \[3Xe{{F}_{4}}+6{{H}_{2}}O\to 2Xe+Xe{{O}_{3}}+12HF+1.5{{O}_{2}}\]
C) \[2Xe{{F}_{2}}+2{{H}_{2}}O\to 2Xe+4HF+{{O}_{2}}\]
D) \[Xe{{F}_{6}}+RbF\to Rb[Xe{{F}_{7}}]\]
Correct Answer: A
Solution :
[a] \[Xe{{F}_{6}}\] has much tendency to hydrolyze. The reverse reaction is more spontaneous. \[Xe{{F}_{6}}+3{{H}_{2}}O\to Xe{{O}_{3}}+6HF\]
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