A) Basicity \[N{{H}_{3}}>P{{H}_{3}}>As{{H}_{3}}>Sb{{H}_{3}}\]
B) Oxidation state of nitrogen \[{{N}_{2}}O<NO<{{N}_{2}}{{O}_{3}}<{{N}_{2}}{{O}_{5}}\]
C) Reducing property of \[{{H}_{3}}P{{O}_{4}}>{{H}_{3}}P{{O}_{3}}>{{H}_{3}}P{{O}_{2}}\]
D) Boiling point of \[Sb{{H}_{3}}>As{{H}_{3}}>N{{H}_{3}}>P{{H}_{3}}\]
Correct Answer: C
Solution :
[c] Reducing property of P oxyacid is due to P-H bonds in the acid, Correct reducing property order is \[{{H}_{3}}P{{O}_{2}}>{{H}_{3}}P{{O}_{3}}>{{H}_{3}}O{{P}_{4}}\]
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