A) B and C
B) Only B
C) A and C
D) Only A
Correct Answer: A
Solution :
[a] \[N{{H}_{4}}N{{O}_{3}}\to 2{{H}_{2}}O+{{N}_{2}}O(A)\] \[4N{{H}_{3}}+5{{O}_{2}}\to 6{{H}_{2}}O+4NO(B)\] \[2Pb{{(N{{O}_{3}})}_{2}}\xrightarrow{\Delta }2PbO+{{O}_{2}}+4N{{O}_{2}}(C)\] Both nitric oxide (NO) and nitrogen dioxide \[(N{{O}_{2}})\]are paramagnetic in nature due to the presence of odd number of electron (S) in outer shell.You need to login to perform this action.
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