A) Cu
B) S
C) C
D) Zn
Correct Answer: C
Solution :
[c] \[{{H}_{2}}S{{O}_{4}}\] is a moderately strong oxidising agent which oxidises both metals and non-metals as shown below \[Cu+2{{H}_{2}}S{{O}_{4}}(conc.)\to CuS{{O}_{4}}+S{{O}_{2}}+2{{H}_{2}}O\]\[S+2{{H}_{2}}S{{O}_{4}}(conc.)\to 3S{{O}_{2}}+2{{H}_{2}}O\] While carbon on oxidation with \[{{H}_{2}}S{{O}_{4}}\]produces two types of oxides \[C{{O}_{2}}\]and\[S{{O}_{2}}\]. \[C+2{{H}_{2}}S{{O}_{4}}(conc.)\to C{{O}_{2}}+2S{{O}_{2}}+2{{H}_{2}}O\]
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