A) remain unchanged if \[{{\gamma }_{V}}={{\gamma }_{L}}\]
B) increase if \[{{\gamma }_{V}}={{\gamma }_{L}}\]
C) decrease if \[{{\gamma }_{V}}={{\gamma }_{L}}\]
D) none of the above
Correct Answer: B
Solution :
[b] Since the vessel is partly filled, volume of the vessel is greater than that of the liquid. When a body having volume V is heated through \[\Delta \theta \], then increase in its volume is given by \[\Delta V=V.\gamma .\Delta \theta \] Since, \[\gamma V=\gamma L\] therefore\[\Delta V\mu V\]. Hence, on heating expansion of vessel will be greater than that of liquid. It means unoccupied volume will necessarily increase so option (2) is correct.
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