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NEET Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Mock Test - Thermal Properties of Matter

  • question_answer
    An external pressure \[P\] is applied on a cube at \[0{}^\circ C\]so that it is equally compressed from all sides. K is the bulk modulus of the material of the cube and a is its coefficient of linear expansion. Suppose we want to bring the cube to its original size by heating. The temperature should be raised by

    A) \[\frac{3\alpha }{PK}\]             

    B) \[3PK\alpha \]

    C) \[\frac{P}{3\alpha K}\]  

    D) \[\frac{P}{\alpha K}\]

    Correct Answer: C

    Solution :

    [c] Due to thermal expansion \[\frac{\Delta V}{V}=3\alpha \Delta T\]                            ...(1) Volumetric strain due to external pressure \[\frac{\Delta V}{V}=\frac{P}{K}\]                                 ...(2) Equating both equations we get \[3\alpha \Delta T=\frac{P}{K}\Rightarrow \Delta T=\frac{P}{3\alpha K}\]


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