A) \[\frac{1}{86400}/k{}^\circ C\]
B) \[\frac{1}{43200}/k{}^\circ C\]
C) \[\frac{1}{14400}/k{}^\circ C\]
D) \[\frac{1}{28800}/k{}^\circ C\]
Correct Answer: A
Solution :
[a] Loss of time due to heating a pendulum is given as \[\Delta T=\frac{1}{2}\alpha \Delta \theta T\] \[\Rightarrow 12.5=\frac{1}{2}\times \alpha \times (25-0){}^\circ C\times 86400\] \[\Rightarrow \alpha =\frac{1}{86400}/{}^\circ C\]You need to login to perform this action.
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