A) \[\frac{72}{7}\frac{r\rho c}{\sigma }\]
B) \[\frac{7}{72}\frac{r\rho c}{\sigma }\]
C) \[\frac{27}{7}\frac{r\rho c}{\sigma }\]
D) \[\frac{7}{27}\frac{r\rho c}{\sigma }\]
Correct Answer: B
Solution :
[b] \[\frac{dT}{dt}=\frac{\sigma A}{mcJ}({{T}^{4}}-{{T}_{0}}^{4})\][in the given problem, fall in temperature of body \[dT=(200-100)=100K,\] tem. Of surrounding \[{{T}_{0}}=0K\], initial temperature of body \[T=200\text{ }K\]] \[\frac{100}{dt}=\frac{\sigma 4\pi {{r}^{2}}}{\frac{4}{3}\pi {{r}^{3}}\rho cJ}({{200}^{4}}-{{0}^{4}})\] \[\Rightarrow dt=\frac{r\rho cJ}{48\sigma }\times {{10}^{-6}}s=\frac{r\rho c}{\sigma }.\frac{4.2}{48}\times {{10}^{-6}}\] \[=\frac{7}{80}\frac{r\rho c}{\sigma }\mu s\approx \frac{7}{72}\frac{r\rho c}{\sigma }\mu s[AsJ=4.2]\]You need to login to perform this action.
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