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NEET Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Mock Test - Thermal Properties of Matter

  • question_answer
    A clock with a metal pendulum beating seconds keeps correct time at\[0{}^\circ C\]. If it loses 12.5 s a day at\[25{}^\circ C\], the coefficient of linear expansion of metal of pendulum is

    A) \[\frac{1}{86400}/k{}^\circ C\]

    B) \[\frac{1}{43200}/k{}^\circ C\]

    C) \[\frac{1}{14400}/k{}^\circ C\]

    D) \[\frac{1}{28800}/k{}^\circ C\]

    Correct Answer: A

    Solution :

    [a] Loss of time due to heating a pendulum is given as \[\Delta T=\frac{1}{2}\alpha \Delta \theta T\] \[\Rightarrow 12.5=\frac{1}{2}\times \alpha \times (25-0){}^\circ C\times 86400\] \[\Rightarrow \alpha =\frac{1}{86400}/{}^\circ C\]


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