A) \[\vec{b}\cdot \vec{n}=0,\,\,\vec{a}\cdot \vec{n}=q\]
B) \[\vec{b}\cdot \vec{n}\ne 0,\,\,\vec{a}\cdot \vec{n}\ne q\]
C) \[\vec{b}\cdot \vec{n}=0,\,\,\vec{a}\cdot \vec{n}\ne q\]
D) \[\vec{b}\cdot \vec{n}\ne 0,\,\,\vec{a}\cdot \vec{n}=q\]
Correct Answer: C
Solution :
[c] We must have \[\vec{b}\cdot \vec{n}=0\] (because the line and the plane must be parallel) and \[\vec{b}\cdot \vec{n}\ne q\](as point \[\vec{a}\] on the line should not lie on the plane).
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