A) \[\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=3\]
B) \[ax+by+cz=3\]
C) \[ax+by+cz={{a}^{2}}+{{b}^{2}}+{{c}^{2}}\]
D) \[ax+by+cz=a+b+c\]
Correct Answer: C
Solution :
[c] Direction ratios of OP are (a, b, c) Therefore, equation of the plane is \[a(x-a)+b(y-b)+c(z-c)=0\] i.e., \[xa+yb+zc={{a}^{2}}+{{b}^{2}}+{{c}^{2}}\]
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