JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Mock Test - Three Dimensional Geometry

  • question_answer
    The length of projection of the line segment joining the points \[\left( 1,\text{ }0,\,\,-1 \right)\] and \[\left( -1,\,\,2,\,\,2 \right)\] on the plane \[x+3y-5z=6\] is equal to

    A) 2                     

    B) \[\sqrt{\frac{271}{53}}\]

    C) \[\sqrt{\frac{472}{31}}\]

    D) \[\sqrt{\frac{474}{35}}\]

    Correct Answer: D

    Solution :

    [d] Let \[A\,\,\left( 1,\,\,0,\,-1 \right),\text{ }B\,\,\left( -1,\text{ }2,\text{ }2 \right)\] Direction ratios of segment AB are \[<2,-2,-\,3>.\] \[\therefore \,\,\,\cos \theta \frac{\left| 2\times 1+3(-2)-5(-\,3) \right|}{\sqrt{1+9+25}\,\sqrt{4+4+9}}\] \[=\frac{11}{\sqrt{17}\sqrt{35}}\] \[=\frac{11}{\sqrt{595}}\] Length of projection\[=(AB)sin\theta \] \[=\sqrt{({{2}^{2}})+{{(2)}^{2}}+{{(3)}^{2}}}\times \sqrt{1-\frac{121}{595}}\] \[=\sqrt{17}\frac{\sqrt{474}}{\sqrt{17}\sqrt{35}}\] \[=\sqrt{\frac{474}{35}}\] Units


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