A) \[\frac{3\pi }{4}\]
B) \[\pi \]
C) \[\frac{3\pi }{2}\]
D) \[\frac{5\pi }{4}\]
Correct Answer: C
Solution :
[c] \[2\left| \sin 2\alpha \right|\le 2\] And \[\left| \tan \beta +\cot \beta \right|=\frac{1}{\sin \beta \cos \beta }=2\cos ec2\beta \ge 2\] \[\therefore \,2\left| \sin 2\alpha \right|=\left| \tan \beta +\cot \beta \right|=2\] \[\therefore \,\alpha =\beta =\frac{3\pi }{4}\]
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