JEE Main & Advanced Mathematics Trigonometric Identities Question Bank Mock Test - Trigonometric Functions

  • question_answer
    The most general value for which tan\[\theta \]=-1\[\cos \theta =\frac{1}{\sqrt{2}}\]is (n\[\in \]z)

    A) \[n\pi =\frac{7\pi }{4}\] 

    B) \[n\pi +{{(-1)}^{n}}\frac{7\pi }{4}\]

    C) \[2n\pi {{+}^{}}\frac{7\pi }{4}\]        

    D) none of these

    Correct Answer: C

    Solution :

    [c] Since tan \[\theta \]0, \[\theta \]lies in the fourth quadrant, then \[\theta =7\pi /4\]. Hence, the general value of \[\theta \]is \[2n\pi +7\pi /4,n\in Z.\]


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