A) \[M_{{}}^{1}L_{{}}^{7/2}T_{{}}^{-2}\]
B) \[M_{{}}^{1}L_{{}}^{1/2}T_{{}}^{-2}\]
C) \[M_{{}}^{1}L_{{}}^{5/2}T_{{}}^{-2}\]
D) \[M_{{}}^{1}L_{{}}^{9/2}T_{{}}^{-2}\]
Correct Answer: B
Solution :
[b] Here \[{{x}^{2}}\]has the dimensions of \[{{L}^{2}},B=[{{L}^{2}}]\] Also \[M{{L}^{2}}{{T}^{-2}}=\frac{A{{L}^{1/2}}}{{{L}^{2}}}\]or \[A=M{{L}^{7/2}}{{T}^{-2}}\] \[\therefore \,A\times B=M{{L}^{11/2}}{{T}^{-2}}\]
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