A) \[4.00\text{ }\pm 0.62\]%
B) \[4.00\text{ }\pm 0.82\]%
C) \[4.00\text{ }\pm 3.2\]%
D) \[4.00\text{ }\pm 5.62\]%
Correct Answer: D
Solution :
[d] Relative density \[{{\rho }_{r}}=\frac{{{W}_{1}}}{{{W}_{1}}-{{W}_{2}}}=\frac{8.00}{8.00-6.00}=4.00\] \[\frac{\Delta {{\rho }_{r}}}{{{\rho }_{r}}}\times 100=\frac{\Delta {{W}_{1}}}{{{W}_{1}}}\times 100+\frac{\Delta ({{W}_{1}}-{{W}_{2}})}{{{W}_{1}}-{{W}_{2}}}\times 100\] \[=\frac{0.05}{8.00}\times 100+\frac{0.05+0.05}{2}\times 100=5.62\text{ }\]%\[\therefore {{\rho }_{r}}=4.00\pm 5.62\]%
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