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JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Mock Test - Units Dimenstions and Measurment

  • question_answer
    To determine the Young's modulus of a wire, the formula is \[Y=\frac{F}{A}\times \frac{L}{\Delta L}\]; where L = length, A = area of cross- section of the wire, \[\Delta L\]= change in length of the wire when stretched with a force \[F\]. What is the conversion factor to change it from CGS to MKS system?

    A) 0.1

    B) 0.2

    C) 0.3

    D) 0.4

    Correct Answer: A

    Solution :

    (0.1) \[Y=\frac{F}{A}.\frac{L}{\Delta L}=\frac{dyne}{c{{m}^{2}}}=\frac{{{10}^{-5}}N}{{{10}^{-4}}{{m}^{2}}}=0.1N/{{m}^{2}}\]


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