A) \[M_{{}}^{0}L_{{}}^{1}T_{{}}^{-1}and\,T_{{}}^{-1}\]
B) \[M_{{}}^{0}L_{{}}^{1}T_{{}}^{0}and\,T_{{}}^{-1}\]
C) \[M_{{}}^{0}L_{{}}^{1}T_{{}}^{-1}and\,LT_{{}}^{-2}\]
D) \[M_{{}}^{0}L_{{}}^{1}T_{{}}^{-1}and\,LT_{{}}^{{}}\]
Correct Answer: A
Solution :
[a] Dimension of \[\alpha t=[{{M}^{0}}{{L}^{0}}{{T}^{0}}]\therefore \,\,\,\,[\alpha ]=[{{T}^{-1}}]\] Again\[\left[ \frac{{{v}_{0}}}{a} \right]=[L]\]so \[[{{v}_{0}}]=[L{{T}^{-1}}]\]You need to login to perform this action.
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