A) \[2I\]
B) \[4I\]
C) \[5I\]
D) \[7I\]
Correct Answer: B
Solution :
[b] \[I(\phi )={{I}_{1}}+{{I}_{2}}+2\sqrt{{{I}_{1}}{{I}_{2}}}\cos \phi \] Here, \[{{I}_{1}}=I\]and \[{{I}_{2}}=4I\] At point A, \[\phi =\frac{\pi }{2}\] \[\therefore {{I}_{A}}=I+4I=5I\] At point B, \[\phi =\pi \] \[\therefore {{I}_{B}}=I+4I-4I=I\] \[\therefore {{I}_{A}}-{{I}_{B}}=4I\]
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