A) 256 + 5 Hz
B) 256 + 2 Hz
C) 256 - 2 Hz
D) 256 - 5 Hz
Correct Answer: D
Solution :
[d] Suppose \[{{n}_{p}}\] = frequency of piano =? \[({{n}_{p}}\propto \sqrt{T})\] \[{{n}_{f}}\]= Frequency of tuning fork = 256 Hz x = Beat frequency = 5 bps, which is decreasing \[(5\to 2)\] after changing the tension of piano Wire Also, tension of piano wire is increasing so \[{{n}_{p}}\downarrow \] Hence \[{{n}_{p}}\uparrow -{{n}_{f}}=x\downarrow \to \] Wrong \[{{n}_{f}}-{{n}_{p}}\uparrow =x\downarrow \to \] Correct \[\Rightarrow {{n}_{p}}={{n}_{f}}-x=256-5Hz.\]You need to login to perform this action.
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