A) \[2.45\times {{10}^{-3}}kg\]
B) \[6.45\times {{10}^{-3}}kg\]
C) \[9.89\times {{10}^{-3}}kg\]
D) \[12.89\times {{10}^{-3}}kg\]
Correct Answer: D
Solution :
[d] The change in potential energy during exercise \[\Delta PE=1000\times mgh\] \[=1000\times 10\times 9.8\times 1=98000J\] Mechanical energy per unit mass \[=\frac{2}{100}\times 3.8\times {{10}^{7}}\]\[=7.6\times {{10}^{5}}J/Kg\] \[\therefore \] Fat burn \[=\frac{9800}{7.6\times {{10}^{5}}}=12.89\times {{10}^{-3}}kg\]
You need to login to perform this action.
You will be redirected in
3 sec
