A) \[8\,(\sqrt{2}\mathbf{i}+\mathbf{j}\pm \mathbf{k})\]
B) \[4\,(\sqrt{2}\mathbf{i}+\mathbf{j}\pm \mathbf{k})\]
C) \[\frac{1}{4}(\sqrt{2}\mathbf{i}+\mathbf{j}\pm \mathbf{k})\]
D) \[\frac{1}{8}(\sqrt{2}\mathbf{i}+\mathbf{j}\pm \mathbf{k})\]
Correct Answer: B
Solution :
Trick : Here is the only vector \[4(\sqrt{2}\mathbf{i}+\mathbf{j}\pm \mathbf{k})\], whose length is 8.
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