JEE Main & Advanced Mathematics Vector Algebra Question Bank Modulus of vector Algebra of vectors

  • question_answer
    The direction cosines of the vector \[3\mathbf{i}-4\mathbf{j}+5\mathbf{k}\] are                                                       [Karnataka CET 2000]

    A) \[\frac{3}{5},\,\frac{-4}{5},\frac{1}{5}\]          

    B) \[\frac{3}{5\sqrt{2}},\,\frac{-4}{5\sqrt{2}},\frac{1}{\sqrt{2}}\]

    C) \[\frac{3}{\sqrt{2}},\,\frac{-4}{\sqrt{2}},\,\frac{1}{\sqrt{2}}\]      

    D) \[\frac{3}{5\sqrt{2}},\,\,\frac{4}{5\sqrt{2}},\,\frac{1}{\sqrt{2}}\]

    Correct Answer: B

    Solution :

    Vector \[\overrightarrow{A}=3i-4j+5k\]. We know that direction cosines of \[\overrightarrow{A}\]\[=\frac{3}{\sqrt{{{3}^{2}}+{{4}^{2}}+{{5}^{2}}}},\,\frac{-4}{\sqrt{{{3}^{2}}+{{4}^{2}}+{{5}^{2}}}},\,\frac{5}{\sqrt{{{3}^{2}}+{{4}^{2}}+{{5}^{2}}}}\]   \[=\frac{3}{5\sqrt{2}},\,\frac{-4}{5\sqrt{2}},\,\frac{1}{\sqrt{2}}\].


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