A) \[m=\pm 1\]
B) \[m=\,\,|\mathbf{a}|\]
C) \[m=\frac{1}{|\mathbf{a}|}\]
D) \[m=\pm \,2\]
Correct Answer: C
Solution :
ma is a unit vector if and only if \[|m\,\mathbf{a}|\]Þ \[m\] \[|a|\,=1\] Þ \[m=\frac{1}{|\mathbf{a}|}\].You need to login to perform this action.
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