A) \[\frac{\mathbf{i}-\mathbf{j}}{\sqrt{2}}\]
B) \[ap+bq+cr=0\]
C) \[{{90}^{o}}\]
D) \[\frac{\mathbf{i}+\mathbf{j}}{\sqrt{2}}\]
Correct Answer: D
Solution :
\[\mathbf{a}+\mathbf{b}=4\mathbf{i}+4\mathbf{j},\] therefore unit vector \[\frac{4\,(\mathbf{i}+\mathbf{j})}{\sqrt{32}}=\frac{\mathbf{i}+\mathbf{j}}{\sqrt{2}}.\]
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