A) \[(\cos \theta )\mathbf{i}-(\sin \theta )\,\mathbf{j}\]
B) \[(\sin \theta )\,\mathbf{i}+(\cos \theta )\,\mathbf{j}\]
C) \[(\sin \,\,2\theta )\,\mathbf{i}-(\cos \theta )\,\mathbf{j}\]
D) \[(\cos \,\,2\theta )\,\mathbf{i}-(\sin \,\,2\theta )\,\mathbf{j}\]
Correct Answer: C
Solution :
Since \[{{\sin }^{2}}2\theta +{{\cos }^{2}}\theta \] is not equal to one necessarily.
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