A) 2, 0
B) 0, ? 2
C) 1, 0
D) 0, ? 1
Correct Answer: D
Solution :
Comparing the coefficients of \[\mathbf{i},\,\,\mathbf{j}\] and \[\mathbf{k},\] the corresponding equations are \[x+3y-4z=\lambda x\] or \[(1-\lambda )x+3y-4z=0\] ......(i) \[x-(\lambda +3)y+5z=0\] ......(ii) \[3x+y-\lambda z=0\] .....(iii) These equations (i), (ii) and (iii) have a non-trivial solution, if \[\left| \begin{matrix} (1-\lambda ) & 3 & -4 \\ 1 & -(\lambda +3) & 5 \\ 3 & 1 & -\lambda \\ \end{matrix} \right|=0\Rightarrow \lambda =0,\,\,-1.\]You need to login to perform this action.
You will be redirected in
3 sec