A) Chlorine
B) Nitrogen
C) Oxygen
D) Hydrogen
Correct Answer: C
Solution :
Oxygen is paramagnetic due to the presence of two unpaired electron: \[{{O}_{2}}=\sigma {{(1s)}^{2}}{{\sigma }^{*}}{{(1s)}^{2}}\sigma {{(2s)}^{2}}{{\sigma }^{*}}{{(2s)}^{2}}\] \[\sigma {{(2{{p}_{x}})}^{2}}\pi {{(2{{p}_{y}})}^{2}}\pi {{(2{{p}_{x}})}^{2}}{{\pi }^{*}}{{(2{{p}_{y}})}^{1}}{{\pi }^{*}}{{(2{{p}_{z}})}^{1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
